1999 CEMC Pascal Problems/Problem 4

Problem

Which of the following numbers divide exactly into $15 + \sqrt{49}$?

$\text{ (A) }\ 3 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ 5 \qquad\text{ (D) }\ 7 \qquad\text{ (E) }\ 11$

Solution

Simplifying $15 + \sqrt{49}$, we get:

$15 + \sqrt{49} = 15 + 7 = 22$

Splitting $22$ into its prime factorization, we get:

$22 = 2 \times 11$

We can now clearly see that $\boxed {\textbf {(E) } 11}$ goes into $22$.

~anabel.disher