2001 CEMC Gauss (Grade 8) Problems/Problem 2

Problem

What number should be placed in the box to make $\frac{6 + \Box}{20} = \frac{1}{2}$

$\text{ (A) }\ 10 \qquad\text{ (B) }\ 4 \qquad\text{ (C) }\ -5 \qquad\text{ (D) }\ 34 \qquad\text{ (E) }\ 14$

Let $x$ be the number represented by the box. We then have:

$\frac{6 + x}{20} = \frac{1}{2}$

$6 + x = \frac{1}{2} \times 20 = 10$

$x = 10 - 6 = \boxed {\textbf {(B) } 4}$

~anabel.disher

2001 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
Preceded by Problem 1	Followed by Problem 3
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CEMC Gauss (Grade 8)