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2001 CEMC Pascal Problems/Problem 1

Problem

The value of $\frac{5(6) - 3(4)}{6 + 3}$ is

$\text{ (A) }\ 1 \qquad\text{ (B) }\ 2 \qquad\text{ (C) }\ 6 \qquad\text{ (D) }\ 12 \qquad\text{ (E) }\ 31$

Solution

$\frac{5(6) - 3(4)}{6 + 3} = \frac{30 - 12}{9} = \frac{18}{9} = \boxed {\textbf {(B) } 2}$

~anabel.disher

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