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2001 CEMC Pascal Problems/Problem 3

Problem

Evaluate $\frac{2^5 - 2^3}{2^2}$.

$\text{ (A) }\ 6 \qquad\text{ (B) }\ 1 \qquad\text{ (C) }\ \frac{1}{4} \qquad\text{ (D) }\ 0 \qquad\text{ (E) }\ 30$

Solution 1

$\frac{2^5 - 2^3}{2^2} = \frac{32 - 8}{4} = \frac{24}{4} = \boxed {\textbf {(A) } 6}$

~anabel.disher

Solution 2

$\frac{2^5 - 2^3}{2^2} = 2^{5 - 2} - 2^{3 - 2} = 2^3 - 2^1 = 8 - 2 = \boxed {\textbf {(A) } 6}$

~anabel.disher

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