2003 AIME II Problems/Problem 3
Contents
Problem
Define a as a sequence of letters that consists only of the letters
,
, and
- some of these letters may not appear in the sequence - and in which
is never immediately followed by
,
is never immediately followed by
, and
is never immediately followed by
. How many seven-letter good words are there?
Solution 1
There are three letters to make the first letter in the sequence. However, after the first letter (whatever it is), only two letters can follow it, since one of the letters is restricted. Therefore, the number of seven-letter good words is
Therefore, there are seven-letter good words.
Solution 2 (Recursion)
We solve this problem using recursion. Let be the number of
-letter good words. Thus
(A, B or C) and the answer is just
. The recurrence relation can be found by considering the last letter of one of the valid strings of length
. There are
possibilities for the next letter and thus
. Now we can find a closed form as
(easy to prove by induction) and thus
seven-letter good words. ~AK2006
Solution 3
This restriction forces the letters to appear in in a fixed cyclic order:
For example, if a word starts with
,
The word's structure is therefore determined by the starting letter and where the block transitions occur. In a letter word, there are
gaps between the letters. At each gap, we can either stay in the block or move on to the next. This gives
choices for each gap, or
possibilities. Multiply this by the
possible starting letters to get
.
~lprado
Video Solution by Sal Khan
https://www.youtube.com/watch?v=JU67TL2L1CA&list=PLSQl0a2vh4HCtW1EiNlfW_YoNAA38D0l4&index=9 - AMBRIGGS
See also
2003 AIME II (Problems • Answer Key • Resources) | ||
Preceded by Problem 2 |
Followed by Problem 4 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 | ||
All AIME Problems and Solutions |
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.