2005 CEMC Pascal Problems/Problem 3

Problem

When $x = 3$, the value of $x(x - 1)(x - 2)(x - 3)(x - 4)$ is

$\text{ (A) }\ 6 \qquad\text{ (B) }\ -6 \qquad\text{ (C) }\ 0 \qquad\text{ (D) }\ 24 \qquad\text{ (E) }\ -24$

Solution

Since the factored form of the expression contains $(x - 3)$, we can see that $x = 3$ must be a root. Thus, plugging in $x = 3$ gives $\boxed {\textbf {(C) } 0}$.

~anabel.disher