2006 CEMC Pascal Problems/Problem 4

Problem

If $A + B = 5$, then the value of $B - 3 + A$ is

$\text{ (A) }\ 2 \qquad\text{ (B) }\ 8 \qquad\text{ (C) }\ 7 \qquad\text{ (D) }\ 15 \qquad\text{ (E) }\ 13$

Solution

To make the problem easier, we can rearrange the terms in the expression to see that the expression is also $A + B - 3$. We can now see that we can plug in $A + B = 5$ into the expression:

$A + B - 3 = 5 - 3 = \boxed {\textbf {(A) } 2}$

~anabel.disher