2010 CEMC Pascal Problems/Problem 1

Problem

Which of the following is closest in value to $$1.00$ ?

$\text{ (A) }\ $0.50 \qquad\text{ (B) }\ $0.90 \qquad\text{ (C) }\ $0.95 \qquad\text{ (D) }\ $1.01 \qquad\text{ (E) }\ $1.15$

We can use the positive difference of each number when subtracted by $$1.00$ using the absolute value function, and see what the lowest number is:

$|$0.50 - $1.00| = |-$0.50| = $0.50$

$|$0.90 - $1.00| = |-$0.10| = $0.10$

$|$0.95 - $1.00| = |-$0.05| = $0.05$

$|$1.01 - $1.00| = |$0.01| = $0.01$

$|$1.15 - $1.00| = |$0.15| = $0.15$

The smallest difference came from $\boxed {\textbf {(D) } $0.01}$ .

~anabel.disher