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2010 CEMC Pascal Problems/Problem 2

Problem

The value of $\frac{(20 - 16) \times (12 + 8)}{4}$ is

$\text{ (A) }\ 5 \qquad\text{ (B) }\ 9 \qquad\text{ (C) }\ 20 \qquad\text{ (D) }\ 44 \qquad\text{ (E) }\ 56$

Solution

Using order of operations, we have

$\frac{(20 - 16) \times (12 + 8)}{4} = \frac{4 \times 20}{4}$

The $4$s cancel out, giving $20$ as our final answer.

~anabel.disher

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