2025 CEMC Pascal Problems/Problem 1

Problem

The value of $(2 \times 0) + (2 \times 5)$ is

$\text{ (A) }\ 0 \qquad\text{ (B) }\ 7 \qquad\text{ (C) }\ 10 \qquad\text{ (D) }\ 12 \qquad\text{ (E) }\ 20$

Following order of operations, we have:

$(2 \times 0) + (2 \times 5) = 0 + (2 \times 5) = 0 + 10 = \boxed {\textbf {(C) } 10}$

~anabel.disher

We can notice that this is the same thing as $2 \times (0 + 5)$ because we get $2 \times 0 + 2 \times 5$ .

$2 \times (0 + 5) = 2 \times 5 = \boxed {\textbf {(C) } 10}$

~anabel.disher