AoPS Wiki talk:Problem of the Day/June 4, 2011

Problem

AoPSWiki:Problem of the Day/June 4, 2011

Answer

$\boxed{\frac{3}{10}}$ Template:Toadd

Solution

Since $0<x<1$ , $\lfloor x\rfloor=0$ and $\lceiling x\rceiling=1$ (Error compiling LaTeX. Unknown error_msg), the equation becomes $10x^2+\frac{0}{1}=\frac{9}{10}$ $10x^2=\frac{9}{10}$ $x^2=\frac{9}{100}$ $x=\boxed{\frac{3}{10}}$

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AoPS Wiki talk:Problem of the Day/June 4, 2011

Problem

Answer

Solution