Difference between revisions of "1981 AHSME Problems/Problem 6"
Coolmath34 (talk | contribs) (Created page with "==Problem== If <math>\frac{x}{x-1} = \frac{y^2 + 2y - 1}{y^2 + 2y - 2},</math> then <math>x</math> equals <math>\text{(A)} \quad y^2 + 2y - 1</math> <math>\text{(B)} \quad y...") |
J314andrews (talk | contribs) (→Solution) |
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| + | ==See also== | ||
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| + | {{AHSME box|year=1981|before=5|num-a=7}} | ||
| + | {{MAA Notice}} | ||
Revision as of 12:35, 28 June 2025
Problem
If
then
equals
Solution
We can cross multiply both sides of the equation and simplify.
The answer is
-edited by coolmath34
See also
| 1981 AHSME (Problems • Answer Key • Resources) | ||
| Preceded by 5 |
Followed by Problem 7 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
| All AHSME Problems and Solutions | ||
These problems are copyrighted © by the Mathematical Association of America, as part of the American Mathematics Competitions.