Difference between revisions of "1983 AHSME Problems/Problem 5"

Revision as of 19:28, 18 May 2016

Problem 5

Triangle $ABC$ has a right angle at $C$ . If $\sin A = \frac{2}{3}$ , then $\tan B$ is

$\textbf{(A)}\ \frac{3}{5}\qquad \textbf{(B)}\ \frac{\sqrt 5}{3}\qquad \textbf{(C)}\ \frac{2}{\sqrt 5}\qquad \text{(D)}\ \sqrt{3}\qquad \text{(E)}\ 2$

Solution

$[asy] pair A,B,C; C = (0,0); B = (3,0); A = (0,1); draw(A--B--C--A); draw(rightanglemark(B,A,C,8)); label("$A$",A,SW); label("$B$",B,SE); label("$C$",C,N); label("$3$",B/2,S); label("$1$",C/2,W); label("$\sqrt{10}$",(C+B)/2,NE); [/asy]$

1983 AHSME (Problems • Answer Key • Resources)
Preceded by Problem 4	Followed by Problem 6
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All AHSME Problems and Solutions

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Difference between revisions of "1983 AHSME Problems/Problem 5"

Revision as of 19:28, 18 May 2016

Problem 5

Solution

See Also

@@ Line 6: / Line 6: @@
 <asy>
 pair A,B,C;
-A = (0,0);
+C = (0,0);
 B = (3,0);
-C = (0,1);
+A = (0,1);
 draw(A--B--C--A);
 draw(rightanglemark(B,A,C,8));