Difference between revisions of "Vieta's formulas"

(Intermediate Level)
Line 16: Line 16:
 
This can be used in a variety of problems, such as :  
 
This can be used in a variety of problems, such as :  
  
== Intermediate Level ==
+
== Intermediate Level ==\\
AIME I 2001/3
+
AIME I 2001/3\\
AIME I 2014/5
+
AIME I 2014/5\\
AIME 1996/5
+
AIME 1996/5\\
AIME I 2005/8
+
AIME I 2005/8\\
AIME 1993/5
+
AIME 1993/5\\
AIME II 2008/7
+
AIME II 2008/7\\
 
+
\\
Try these out!
+
Try these out!\\
 
+
\\
 
This theorem relates to polynomials
 
This theorem relates to polynomials
 
{{stub}}
 
{{stub}}

Revision as of 10:57, 15 October 2025

Theorem 14.1.4 (Vieta’s Formula For Higher Degree Polynomials) In a polynomial $a_n x^n + a_{n-1} x ^ {n-1} ..... a_1 x^{1} + a_0$ with roots $r_1 r_2 r_3 ... r_n$

the following holds:

\begin{align*} r_1 + r_2 + r_3 + \cdots + r_n (the sum of all terms) &= −\frac{a_{n−1}}{a_n} \\ r_1r_2 + r_1r_3 + \cdots + r_{n−1}r_n (the sum of all products of 2 terms) &= \frac{a_{n−2}}{a_n} \\ r_1r_2r_3 + r_1r_2r_4 + \cdots + r_{n−2}r_{n−1}r_n (the sum of all products of 3 terms) &= −\frac{a_{n−3}{a_n} \\ &\vdots \\ r_1r_2r_3 \cdots r_n (the sum of all products of n terms) &= (−1)^n \frac{a_0}{a_n} \end{align*}

Note that the negative and positive signs alternate. When summing the products for odd number of terms, we will have a negative sign otherwise we will have a positive sign.

This can be used in a variety of problems, such as :

== Intermediate Level ==\\ AIME I 2001/3\\ AIME I 2014/5\\ AIME 1996/5\\ AIME I 2005/8\\ AIME 1993/5\\ AIME II 2008/7\\ \\ Try these out!\\ \\ This theorem relates to polynomials This article is a stub. Help us out by expanding it.