2001 CEMC Gauss (Grade 8) Problems/Problem 3

The following problem is from both the 2001 CEMC Gauss (Grade 8) #3 and 2001 CEMC Gauss (Grade 7) #5, so both problems redirect to this page.

Problem

The value of $3 \times 4^2 - (8 \div 2)$ is

$\text{ (A) }\ 44 \qquad\text{ (B) }\ 12 \qquad\text{ (C) }\ 20 \qquad\text{ (D) }\ 8 \qquad\text{ (E) }\ 140$

Solution

Following order of operations, we have:

$3 \times 4^2 - (8 \div 2) = 3 \times 4^2 - 4 = 3 \times 16 - 4$

$=48 - 4 = \boxed {\textbf {(A) } 44}$

~anabel.disher

2001 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)
2001 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 7)