2002 CEMC Gauss (Grade 8) Problems/Problem 6

The following problem is from both the 2002 CEMC Gauss (Grade 8) #6 and 2002 CEMC Gauss (Grade 7) #12, so both problems redirect to this page.

Problem

Qaddama is $6$ years older than Jack. Jack is $3$ years younger than Doug. If Qaddama is $19$ years old, how old is Doug?

$\textbf{(A)}\ 17 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 10 \qquad\textbf{(D)}\ 18 \qquad\textbf{(E)}\ 15$

Solution 1

Since Qaddama is $6$ years older than Jack, Jack's age must be $6$ less than Qaddama's age. Thus, Jack's age is $19 - 6 = 13$.

Since Jack is $3$ years younger than Doug, Doug's age must be $3$ more than Jack's age. Thus, Doug's age is $13 + 3 = \boxed {\textbf {(B) } 16}$.

~anabel.disher

Solution 2 (using a variable)

Let $a$ be Qaddama's age.

Since Qaddama is $6$ years older than Jack, Jack's age is $a - 6$.

Since Jack is $3$ years younger than Doug, Doug's age is $a - 6 + 3 = a - 3$.

We can now plug-in $a = 19$ because we know that's Qaddama's age from the third sentence of the problem. We then see that Doug's age is $a - 3 = 19 - 3 = \boxed {\textbf {(B) } 16}$.

~anabel.disher

2002 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 5
Followed by
Problem 7
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)
2002 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 7)