2014 CEMC Gauss (Grade 8) Problems/Problem 6
Problem
The value of
that satisfies the equation
is
Solution 1
Adding
to both sides, we get:
~anabel.disher
Solution 2
All of the terms as well as the coefficient of
is divisible by
. Dividing both sides by
, we get:
~anabel.disher
Solution 3 (answer choices)
We can notice that
. This means the answer for
cannot be less than
, eliminating choices D and E.
We can now try
since it is the median of the answer choices (excluding the eliminated choices) and then check whether or not the value found for
is too large, too small, or is correct. This gives:
This is equal to
. Thus, the answer is
.
~anabel.disher
| 2014 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources) | ||
| Preceded by Problem 5 |
Followed by Problem 7 | |
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| CEMC Gauss (Grade 8) | ||