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Difference between revisions of "2014 CEMC Gauss (Grade 8) Problems/Problem 2"

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{{CEMC box|year=2014|competition=Gauss (Grade 7)|num-b=4|num-a=6}}

Revision as of 13:56, 17 October 2025

Problem

One scoop of fish food can feed 8 fish. How many goldfish can 4 scoops of fish food feed?

$\textbf{(A)}\ 12 \qquad\textbf{(B)}\ 16 \qquad\textbf{(C)}\ 8 \qquad\textbf{(D)}\ 64 \qquad\textbf{(E)}\ 32$

Solution

$1 \text{ scoop} = 8 \text{ goldfish}$

$4 \text { scoops} = 8 \times 4 \text { goldfish} = \boxed {\textbf {(E) } 32} \text { goldfish}$

~anabel.disher

2014 CEMC Gauss (Grade 8) (ProblemsAnswer KeyResources)
Preceded by
Problem 1
Followed by
Problem 3
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 8)
2014 CEMC Gauss (Grade 7) (ProblemsAnswer KeyResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
CEMC Gauss (Grade 7)