Difference between revisions of "2001 CEMC Gauss (Grade 8) Problems/Problem 7"
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<math>r + 15 = 25</math> | <math>r + 15 = 25</math> | ||
| − | <math>r = 10</math> | + | <math>r = \boxed {\textbf {(B) } 10}</math> |
~anabel.disher | ~anabel.disher | ||
{{CEMC box|year=2001|competition=Gauss (Grade 8)|num-b=6|num-a=8}} | {{CEMC box|year=2001|competition=Gauss (Grade 8)|num-b=6|num-a=8}} | ||
{{CEMC box|year=2001|competition=Gauss (Grade 7)|num-b=8|num-a=10}} | {{CEMC box|year=2001|competition=Gauss (Grade 7)|num-b=8|num-a=10}} | ||
Latest revision as of 17:28, 20 October 2025
- The following problem is from both the 2001 CEMC Gauss (Grade 8) #7 and 2001 CEMC Gauss (Grade 7) #9, so both problems redirect to this page.
Problem
The bar graph shows the hair colours of the campers at Camp Gauss. The bar corresponding to redheads has been accidentally removed. If 
of the campers have brown hair, how many of the campers have red hair?
An image is supposed to go here. You can help us out by creating one and editing it in. Thanks.
Solution 1
Let 
be the number of people with red hair. Since or half of the campers have brown hair, the total number of campers of the other hair colors must also be 
. Thus, we have:
~anabel.disher
| 2001 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources) | ||
| Preceded by Problem 6 |
Followed by Problem 8 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| CEMC Gauss (Grade 8) | ||
| 2001 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources) | ||
| Preceded by Problem 8 |
Followed by Problem 10 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||
| CEMC Gauss (Grade 7) | ||
