2014 CEMC Gauss (Grade 8) Problems/Problem 19

The following problem is from both the 2014 CEMC Gauss (Grade 8) #19 and 2014 CEMC Gauss (Grade 7) #21, so both problems redirect to this page.

Problem

A bicycle at Store P costs $$200$ . The regular price of the same bicycle at Store Q is $15\%$ more than it is at Store P. The bicycle is on sale at Store Q for $10\%$ off of the regular price. What is the sale price of the bicycle at Store Q?

$\textbf{(A)}\ $230.00 \qquad\textbf{(B)}\ $201.50 \qquad\textbf{(C)}\ $199.00 \qquad\textbf{(D)}\ $207.00 \qquad\textbf{(E)}\ $210.00$

Solution

First, we can find the regular price of the bicycle at Store Q. Then, we can figure out the sale price from that regular price.

Since the bicycle costs $$200.00$ at Store P and costs $15\%$ more at Store Q than it does at Store P, the regular price of the bicycle at Store Q is:

$$200.00 + $200.00 \times 15\% = $200 \times 1.15 = $230.00$

Next, the sales price is $10\%$ off this regular price at Store Q. We then have:

$$230.00 - $230.00 \times 10\% = $230.00 - $23.00 = \boxed {\textbf {(D) } $207.00}$

~anabel.disher

2014 CEMC Gauss (Grade 8) (Problems • Answer Key • Resources)
Preceded by Problem 18	Followed by Problem 20
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CEMC Gauss (Grade 8)

2014 CEMC Gauss (Grade 7) (Problems • Answer Key • Resources)
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CEMC Gauss (Grade 7)

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2014 CEMC Gauss (Grade 8) Problems/Problem 19

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